Unity/C# 언어
pow 제곱 연산
하얀소닉
2014. 4. 4. 16:42
void pow2(){ int i=0;; int num = 1; string a; for(num=1;num<2048;num = num * 2,i = i +1){ a ="Pow (2."+ i + ")= " +num; print (a); } } void pow(){ int i = 0; int num = 1; string a; while(true) { a = "Pow (2, " + i + " ) = "+num; print (a); i = i+1;// = i++; num = num * 2; if(num> 2048) break; } }